Descriptive Statistics in Economics
Before you do any fancy analysis — first, just look at your data!
Before you do any fancy analysis — first, just look at your data!
Imagine you’re a doctor. Before you diagnose someone, you take their temperature, check their pulse, look at their weight. You don’t just jump straight to surgery. You describe what’s going on first.
Descriptive statistics is exactly that for economists. Before you run any regressions or complicated models, you summarise your data. You look at the shape of it. You spot the weird values. You understand what you’re working with.
And here’s the thing — sometimes the descriptive stats alone tell you everything you need to know. When researchers found that the average US household income was $105,000 but the typical household earns closer to $74,000, that gap alone revealed something huge about inequality. No regression required.
x̄ = (x₁ + x₂ + … + xₙ) / n
The mean is what most people call “the average.” It’s dead simple to calculate. But here’s its weakness: it’s easily dragged around by extreme values.
Classic example: imagine a room with 9 ordinary people earning £30,000 a year and one billionaire earning £1 billion. The average income in that room is over £100 million. Does that represent anyone in the room? Nope. The billionaire is pulling the whole thing upward.
The median ignores the extremes. It just finds the person in the middle of the line. In that same room? The median is £30,000 — which actually represents what most people earn.
This is why governments and economists often use the median household income rather than the mean. The mean flatters inequality.
G = (x₁ × x₂ × … × xₙ)^(1/n)
You use this for growth rates over time. If your investment grew by 50% one year and dropped by 33% the next, the arithmetic average is +8.5%. But your actual return is 0% — because 1.5 × 0.67 = 1.0. The geometric mean correctly captures compound growth. Most financial returns and GDP growth figures should use this.
The mean tells you the centre. But how spread out are the values around that centre? That’s what variance and standard deviation measure.
Think of two countries with average incomes of £30,000. In Country A, almost everyone earns between £28,000 and £32,000. In Country B, half the population earns £5,000 and the other half earns £55,000. The mean is the same, but Country B has massively more inequality. The standard deviation reveals this.
Sample variance: s² = Σ(xᵢ − x̄)² / (n−1)
Standard deviation: s = √s²
Why divide by (n−1) instead of n? Because with a sample (not the full population), dividing by n gives you a slightly too-small estimate. Using (n−1) corrects for this. It’s called Bessel’s correction. Just remember it — it won’t come up often, but examiners love to ask about it.
Inflation rates over 5 years: 2%, 4%, 3%, 6%, 5%.
So on average, inflation was 4% per year, give or take about 1.58 percentage points.
CV = (standard deviation / mean) × 100
If wages in the UK have a mean of £35,000 and SD of £10,000, and wages in Pakistan have a mean of £8,000 and SD of £5,000, which country has more wage inequality? You can’t just compare the SDs — the scales are different. The CV lets you compare: UK = 28.6%, Pakistan = 62.5%. Pakistan has proportionally more wage inequality.
A perfectly symmetric distribution (like a bell curve) has skewness = 0. But economic data is rarely perfectly symmetric.
Kurtosis measures whether extreme values (outliers) happen more or less often than you’d expect if the data were normally distributed.
Every year, the UK’s Office for National Statistics publishes data on household incomes. Here’s what the 2022/23 data showed:
| Statistic | Value | What it means |
|---|---|---|
| Mean income | £38,500 | Pulled up by the wealthy |
| Median income | £31,400 | What the typical household actually earns |
| Gap (mean/median) | 1.23× | Tells us the distribution is right-skewed |
| Gini coefficient | 0.35 | 0 = perfect equality; 1 = perfect inequality |
| Top 10% vs bottom 10% | 4.2× ratio | The richest earn 4.2× the poorest |
Now imagine a politician says “average household income rose by 5% this year!” — but that rise was entirely in the top 10% of earners. The median might have barely moved. This is exactly why economists like Anthony Atkinson (2015) argued we should report median income and the income of the poorest 10% as our main welfare indicators, not the mean.
The right-skew in UK income data also means standard OLS regression models may behave poorly on raw income figures — you’d usually log-transform income before using it in any analysis.
Sources: ONS (2023). Household income inequality, UK: Financial year ending 2023. Atkinson, A.B. (2015). Inequality: What Can Be Done? Harvard University Press.
GDP growth rates for 6 years: 2.1%, 3.4%, −0.8%, 4.2%, 3.1%, 2.6%. Find the (a) mean, (b) median, (c) sample standard deviation.
(a) Mean: (2.1 + 3.4 − 0.8 + 4.2 + 3.1 + 2.6) / 6 = 14.6 / 6 = 2.43%
(b) Median: Sort them: −0.8, 2.1, 2.6, 3.1, 3.4, 4.2. Two middle values = 2.6 and 3.1. Median = (2.6 + 3.1)/2 = 2.85%
(c) Standard deviation:
Deviations from mean (2.43): −3.23, −0.33, +0.17, +0.67, +0.97, +1.77
Squared: 10.43, 0.11, 0.03, 0.45, 0.94, 3.13 → Sum = 15.09
Variance = 15.09 / 5 = 3.02 → SD = √3.02 = 1.74%
A report says “average income in the country rose by 8% this year.” A student claims this means everyone is 8% better off. Is the student right? What statistical concept explains why they might be wrong?
The student is wrong. Income distributions are positively skewed — a few very high earners can pull the mean up significantly without most people being better off at all. If the top 1% of earners received massive pay rises while everyone else stayed flat, the average (mean) could rise by 8% even though the median barely moved.
The concept is positive skewness — where the mean > median. To say “everyone is better off,” you’d want to see the median income rising, and ideally the income of the bottom decile (P10) rising too. The mean alone is a misleading welfare indicator when distributions are skewed.
Daily stock returns have excess kurtosis of 5.8. Explain what this means and why a risk manager who assumes returns are normally distributed might get into serious trouble.
Excess kurtosis of 5.8 means the distribution has fat tails — extreme returns (both big gains and big losses) occur much more frequently than a normal distribution would predict. The distribution is leptokurtic.
A risk manager assuming normality would calculate, say, a “maximum daily loss” that should happen only once in a thousand days. But with fat tails, that loss might happen once a month. They would hold too little capital in reserve — dramatically underestimating tail risk. This is essentially what happened to many financial institutions in 2008. Their Value-at-Risk models assumed normal distributions. Reality had fat tails. The models failed catastrophically.
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